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A block of mass $m$ is released from point $A$ on inclined plane whose first half is smooth and next half is rough and its coefficient of friction is $μ = x \tan θ$ then $x =$ _________if the block stops at bottom $B$ .

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answer is 2.

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Detailed Solution

$w_{n c} = k_{f} - k_{i} + v_{f} - v_{i}$
$- 3 μ m g \cos θ \times \frac{l}{2} = - m g l \sin θ$
$μ = 2 \tan θ$
$∴ x = 2$

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