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A block of mass $m$ is suspended from a spring as shown in the figure. It executes SHM of time period T. The amplitude of the SHM is A. The spring is never in compressed state during the oscillation. The minimum force exerted by spring on the block is

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$m g - \frac{4 π^{2}}{T^{2}} m A$

$m g + \frac{4 π^{2}}{T^{2}} m A$

$m g - \frac{7 π^{2}}{4 T^{2}} m A$

$m g + \frac{7 π^{2}}{4 T^{2}} m A$

answer is A.

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Detailed Solution

${kx}_{0} =mg$

The spring is never compressed. Hence, spring shall exert least force on the block when the block is at top extreme.

$F_{min} {=kx}_{0} {-kA=mg-mω}^{2} A=mg- \frac{{4π}^{2}}{T^{2}} mA$

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