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Q.

A block of mass m moving with speed v collides with another block of mass 2m at rest. The lighter block comes to rest after the collision. The coefficient of restitution is

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a

1/4

b

1/3

c

1/5

d

1/2

answer is A.

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Detailed Solution

mv=2mv2⇒v2=v2
e=v2-v1u1-u2=v2-0v-0=12

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