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Q.

A block of mass M placed inside a box descends vertically with acceleration 'a'. The block exerts a force equal to one-fourth of its weight on the floor of the box. The value of 'a' will be

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a

$g$

b

$\frac{g}{2}$

c

$\frac{3 g}{4}$

d

$\frac{g}{4}$

answer is C.

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Detailed Solution

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Question Image

mg – N = ma
$a = g - \frac{g}{4}$
$a = \frac{3 g}{4}$

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