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Q.

A block of mass m slides along a floor while a force of magnitude F is applied to it an angle θ as shown in figure. The coefficient of kinetic friction is μk . Then, the block’s acceleration ‘a’ is given by: (g is acceleration due to gravity)

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a

Fmcosθ+μkg−Fmsinθ

b

Fmcosθ−μkg−Fmsinθ

c

-Fmcosθ−μkg−Fmsinθ

d

Fmcosθ−μkg+Fmsinθ

answer is A.

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Detailed Solution

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N = mg − fsinθ
Fcosθ − μk​N = ma
Fcosθ − μk​(mg − Fsinθ) = ma
a=Fmcosθ−μkg−Fmsinθ

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