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Q.

A block of mass m slides down an inclined plane of inclination θ with uniform speed. The coefficient of friction between the block and the plane is μ . The contact force between the block and the plane is

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a

mgsin⁡θ1+μ2

b

mg

c

mgsin⁡θ

d

(mgsin⁡θ)2+(μmgcos⁡θ)2

answer is D.

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Detailed Solution

Block slides down with constant velocity. Hence, net force on the block is zero.
f=mgsin⁡θ;N=mgcos⁡θ;R=f2+N2

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