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Q.

A block of mass M slides down on a rough inclined plane with constant velocity. The angle made by the incline plane with horizontal is θ. The magnitude of the contact force will be :

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a

Mg sin θ1+μ

b

Mg

c

Mg sin θ + Mg cos θ

d

Mg cos θ

answer is A.

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Detailed Solution

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N=Mg cos θ

Since it is moving with a constant velocity

f=Mg sin θ

R=N2+f2R=Mg

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