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A block of mass $m_{1}$ lies on top of fixed wedge as shown in figure-1 and another block of mass $m_{2}$ lies on top of wedge which is free to move as shown in figure-2. At time $t = 0,$ both the blocks are released from rest from a vertical height h above the respective horizontal surface on which the wedge is placed as shown. There is no friction between block and wedge in both the figures. Let $T_{1}$ and $T_{2}$ be the time taken by block in figure-1 and block in figure-2 respectively to just reach the horizontal surface, then

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Magnitude of normal reaction on block of mass is less than that on the block of mass $m_{1}$ .

$T_{1} < T_{2}$

After falling through same height (less than h)from top of wedge , the speed of block of mass $m_{2}$ is less than that of block of mass $m_{1}$ .

$T_{1} > T_{2}$

answer is A, C, D.

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Detailed Solution

We draw axes for each block along the incline and normal to incline. The component of acceleration for each block are as shown, where a is acceleration of wedge is figure 2.

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