A block of mass 2 kg is hanging over a smooth and light pulley through a light string. The other end of the string is pulled by a constant force F=40 N. The kinetic energy of the particle increase 40 J in a given interval of time. Then :g=10 m/s2

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Q.

A block of mass $2 kg$ is hanging over a smooth and light pulley through a light string. The other end of the string is pulled by a constant force $F = 40 N .$ The kinetic energy of the particle increase $40 J$ in a given interval of time. Then : $(g = 10 m / s^{2})$

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a

displacement of the block in the given interval of time is $2 m$

b

work done by tension is $80 J$

c

work done by gravity is $- 20 J$

d

tension in the string is $40 N$

answer is A, B, D.

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Detailed Solution

Free body diagram of block is as shown in figure.

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From work-energy theorem $W_{net} = Δ KE o r (40 - 20) s = 40$

$∴ s = 2 m$

Work done by gravity is $- 20 \times 2 = - 40 J$

and work done by tension is $40 \times 2 = 80 J$

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A block of mass 2 kg is hanging over a smooth and light pulley through a light string. The other end of the string is pulled by a constant force F=40 N. The kinetic energy of the particle increase 40 J in a given interval of time. Then :g=10 m/s2