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A block of mass $2 k g$ starts moving at $t = 0$ with speed $2 m / s$ on a smooth horizontal surface. A horizontal force $F$ is applied in the direction of velocity which varies with time shown in figure $(b)$ , the speed of particle at $t = 3$ seconds ( $g = 10 m / s^{2}$ )

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$2.5 m / s$

$3.5 m / s$

$4.5 m / s$

None of these

answer is B.

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Detailed Solution

$J = T o t a l a r e a = \frac{1}{2} \times 1 \times 2 \times 3 = 3 N s = 2 \times ∆ V ∆ V = v - 2 = 1.5 \Rightarrow v = 3.5 m / s$

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