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Q.

A block of mass M is moving with a velocity v1 on a frictionless surface as shown in figure. It passes over to a cylinder of radius R and moment of inertia I which has a fixed axis and initially at rest. When it first make contact with the cylinder, it slips on the cylinder, but the friction is large enough so that slipping ceases before it losses contact with the cylinder. Final it goes to the dotted position with velocity v2. Compute v2 in terms of v1, M, I and R.

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a

   v2=v121+lMR2

b

   v2=v14+l2MR2

c

   v2=2v11+lMR2

d

   v2=v11+lMR2

answer is D.

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Detailed Solution

By conservation of angular momentum, we have                          Mv1R=Iω + Mv2R where                     l   = MR22 and                        ω  =v2R Thus,              Mv1R = Iv2R + Mv2R                             v2=v11+lMR2

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