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Q.

A block of weight 100N is lying on a rough horizontal surface. If coefficient of friction $1/ \sqrt{3}$ . The least possible force that can move the block is

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a

50 N

b

100 \sqrt{3}

c

50 \sqrt{3}

d

\frac{100}{\sqrt{3}}

answer is D.

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Detailed Solution

μ_{k} = 1/ \sqrt{3}

$mg = 100 N$

$F_{\min} = \frac{μ mg}{\sqrt{1 + μ^{2}}} = \frac{\frac{1}{\sqrt{3}} \times 100}{2 \sqrt{3}} = 50 N$

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