A block of weight W connected to light string is placed on a wedge as shown in figure. The force F needed to hold the wedge in equilibrium is $\frac{\sqrt{3} W}{n}$ . The value of n is…..(neglect friction everywhere).

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answer is 4.

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Detailed Solution

$\begin{array}{l} N = Wcos θ and Nsin θ = F \\ \Rightarrow Wcos θsin θ = F \\ ⇒ F = W \frac{\sqrt{3}}{2} \cdot \frac{1}{2} \Rightarrow F = \frac{\sqrt{3} W}{4} \end{array}$

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