Q.

A block of wood is floating in water such that 1/2 of it is submerged in water. When the same block is floated in alcohol, l/3rd of it's volume is submerged. Now a mixture of water and alcohol is made taking equal volume of both and block is floated in it. What is the % of it's volume that is now submerged?

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a

60

b

50

c

40

d

30

answer is B.

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Detailed Solution

mg=ρ1×0.5V0gρ1=2mV0mg=ρ2×V03gρ2=3mV0ρ=ρ1V+ρ2V2V=ρ1+ρ22mg=ρVg=ρ1+ρ2Vg2 m=122mV0+3mV0Vm=5mV2V0V=0.4V040%

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