A block of wood is kept on a tabletop.  The mass of wooden block is 5 kg, and its dimensions are 40 cm x 20 cm x 10 cm.  Find the pressure exerted by the wooden block on the tabletop if it is made to lie on the tabletop with its sides of dimensions 20 cm x 10 cm.

The mass of the wooden block = 5 kg

The dimensions = 40 cm x 20 cm x 10 cm

Here, the weight of the wooden block applies a force on the tabletop.

That is, Thrust $\mathrm{F}=\mathrm{m}\times \mathrm{g}$

$=5 \mathrm{kg}\times 9.8{ \mathrm{ms}}^{-2}$

Area of a side = length ´ breadth

$=20 \mathrm{cm}\times 10 \mathrm{cm}$

= 200 cm² = 0.02m²

$\text{ From, Pressure }=\frac{\text{ Force }}{\text{ Area }}$

$\text{ Pressure }=\frac{49 \mathrm{N}}{0.02{ \mathrm{m}}^2}=2450{\mathrm{Nm}}^{-2}$