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A block of $60 k g$ is released from rest when compresson in the spring is $2 m$ (normal length of spring is $8 m$ ). Surface $A B$ is smooth while surface $B C$ is rough. Block travels $x$ distance on rough surface before coming to complete rest. The value of $x$ is : $(g = 10 m / s^{2})$

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$z e r o$

$3 m$

$1 m$

$2 m$

answer is A.

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Detailed Solution

$\frac{1}{2} \times 200 \times 2^{2} = 0.5 \times (60 \times 10) x + \frac{1}{2} 200 x^{2}$

$∴ x = 1 m$

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