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Q.

A block resting on the horizontal surface executes SHM in horizontal plane with amplitude A The frequency of oscillation for which the block just starts to slip is (μ = coefficient of friction, g = gravitational acceleration)

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a

14πμgA

b

12πμgA

c

2πAμg

d

4πAμg

answer is A.

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Detailed Solution

When restoring force will become equal to the frictional force block will start to slip.
     Restoring force = Friction force

                           kA=μmg                             Frestoring =-kx                …(i)

Now,    frequency, f=12πkm

From Eq. (i), we get

                              f=12πμgA

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