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Q.

A block slides down from top of a smooth inclined plane of elevation  θ fixed in an elevator going up with an acceleration  a0. The base of incline has length L. Find the time taken by the block to reach the bottom.

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a

[4L(ga0)sin2θ]12

b

[4L(ga0)sinθ]12

c

[4L(g+a0)sinθ]12

d

[4L(g+a0)sin2θ]12

answer is A.

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Detailed Solution

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net force acting on the body w.r.t lift 

mg+a0

acceleration along the plane g+a0sinθ

length of the plane s=L/cosθ

time taken t= 2sa=2L22cosθg+a0sinθ

t=4Lg+a0sin2θ

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