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Q.

A block starting from rest slides down a rough fixed incline having angle of inclination $53^{0}$ . It covers 12 m in first two seconds i.e. from t = 0 to t = 2 sec. then

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a

Velocity at t = 2 sec will be 12 m/s.

b

Distance covered in next 4 seconds will be 48 m.

c

Coefficient of friction between block & incline will be $\frac{1}{3}$

d

Coefficient of friction between block & incline will be $\frac{2}{3}$

answer is A, C.

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Detailed Solution

$s = u t + \frac{1}{2} a t^{2} 12 = 0 + \frac{1}{2} a . {(2)}^{2} \Rightarrow a = 6 m / s a = g \sin θ - μ g \cos θ 6 = 8 - 6 μ \Rightarrow 6 μ = 2 μ = \frac{1}{3} v = u + a t = 0 + (2) v = 12 m / s s = u t + \frac{1}{2} a t^{2} = 12 (4) + \frac{1}{2} 6 {(4)}^{2} s = 96 m$

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