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A block starts moving up a fixed inclined plane of inclination 60° with a velocity of 20 m/s and stops after 2 sec. The approximate value of coefficient of friction is $(g = 10 m / s^{2})$

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3.3

0.27

0.33

answer is C.

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Detailed Solution

Retardation $= g (sinθ + μcosθ) = 5 (\sqrt{3} + μ)$
Now $v = u - at$
$∴ a = \frac{u}{t} as v = 0$
$∴ 5 (\sqrt{3} + μ) = 10$
$\Rightarrow μ = 0 .27$

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