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A boat man can row with a speed of 10 kmph in still water. River flows at 6 kmph if he crosses the river from one bank to the other along the shortest possible path, time taken to cross that river of width 1 km is

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$\frac{1}{8} h r$

$\frac{1}{2} h r$

$\frac{1}{4} h r$

1 hr

answer is D.

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Detailed Solution

$V_{R} = 6 k m p h, V_{B R} = 10 k m p h, V_{B} = ?$

$V_{B} = \sqrt{V_{B R^{2}} - V_{R^{2}}} = \sqrt{10^{2} - 6^{2}} = 8 k m p h$

$t = \frac{w i d t h}{v e l o c i t y o f b o a t} = \frac{W}{V_{B}} = \frac{1 k m}{8 k m p h} = \frac{1}{8} h r$

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