A boat’s crew consists of 8 men, 3 of whom can only row on one side, 2 only on the other. The number of ways the crew can be arranged.

Let A, B, C, C, D, E, F, G, H be the crew.

Let A, B, C can row on one side and GH can row on other side

Remaining 3 should be divided into 2 groups containing 1, 2 in $\frac{3!}{2! . 1!}=3$ ways.

After distribution crew can be arranged 4 on each side in $4!\times 4!$ Ways.

No of ways $=3\times 4!\times 4!=3\times 24\times 24=1728$