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A boats man finds that he can save 6 sec in crossing a river by quicker path, than by shortest path. If the magnitude velocity of boat relative to still water and magnitude of velocity of river be respectively 17 m/s and 8 m/s, then river width is

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765 m

475 m

585 m

495m

answer is A.

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Detailed Solution

$\Rightarrow \frac{d}{\sqrt{u_{b w}^{2} - u_{w}^{2}}} - \frac{d}{u_{b w}} = 6$

$[\frac{d}{\sqrt{17^{2} - 8^{2}}} - \frac{d}{17} = 6 \Rightarrow \frac{d}{15} - \frac{d}{17} = 6]$

$d = \frac{15 \times 17 \times 6}{2} = 765 m$

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