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A bob is hanging over a pulley inside a car through a string. The other end of the string is in the hands of a person standing in the car. The car is moving with a constant acceleration $a$ directed horizontally as shown in figure. Other end of the string is pulled with a constant acceleration $a$ vertically. The tension in the string is equal to

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$m \sqrt{g^{2} + a^{2}} - m a$

$m (g + a)$

$m \sqrt{g^{2} + a^{2}} + m a$

$m \sqrt{g^{2} + a^{2}}$

answer is C.

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Detailed Solution

$T = m \sqrt{g^{2} + a^{2}}$
$T_{n e t} = m \sqrt{g^{2} + a^{2}} + m a$
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