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A bob is suspended from a crane by a cable of lengtr $I = 5 m$ . The crane and load are moving at a constant speed $v_{0}$ . The crane is stopped by a bumper and the bob on the cable swings out an angle of $60 °$ . Find the initial speed $v_{0} \cdot (g = 9.8 m / s^{2})$

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$2 m / s$

$3 m / s$

$7 m / s$

$5 m / s$

answer is C.

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Detailed Solution

h = l(1-cos $θ$ )

$h = l - l \cos 60 ° = \frac{l}{2} = 2.5 m$

A bob is suspended from a carne by a cable of length l=5m . The carne and load are moving at a constant speed v_(0) The crane is stopped by a bumper

$v_{0} = \sqrt{2 g h} = \sqrt{2 \times 9.8 \times 2.5} = 7 m / s$

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