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A bob of mass 2kg is suspended from the ceiling of a train moving with an acceleration a of $7.5 m / s^{2}$ . The angle $' θ'$ the string attached to the bob makes with the vertical is $(g = 10 m / s^{2})$

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$30^{\circ}$

$37^{0}$

$60^{0}$

$53^{0}$

answer is B.

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Detailed Solution

$θ = {Tan}^{- 1} (\frac{a}{g})$

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