A body A, of mass m = 0.1kg has an initial velocity of 3i^ ms−1. It collides elastically with another body, B of the same mass which an initial velocity of 5j^ms−1. After collision, A moves with a velocity v→=4(i^+j^). The energy of B after collision is written as x10J. The value of x is ________.

Book Online Demo

Check Your IQ

Try Test

Courses

A body A, of mass m = 0.1kg has an initial velocity of $3 \hat{i} {ms}^{- 1}$ . It collides elastically with another body, B of the same mass which an initial velocity of $5 \hat{j} {ms}^{- 1}$ . After collision, A moves with a velocity $\vec{v} = 4 (\hat{i} + \hat{j})$ . The energy of B after collision is written as $\frac{x}{10} J$ . The value of x is ________.

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

answer is 1.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

$Initial momentum : \vec{p_{1}} = m 3 \hat{i} + m 5 \hat{j}$

$final momentum \vec{p_{2}} = m 4 (\hat{i} + \hat{j}) + m \vec{v} where \vec{v} is the velocity of the second body after collision$

$By applying the conservation of linear momentum m 3 \hat{i} + m 5 \hat{j} = m 4 (\hat{i} + \hat{j}) + m \vec{v}$

$\vec{v} = - \hat{i} + \hat{j}$

$kinetic energy = \frac{1}{2} (0.1) (2) = 0.1 J = \frac{x}{10} = \frac{1}{10} so x = 1$

Watch 3-min video & get full concept clarity