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Q.

A body at rest starts rotating with constant angular acceleration. The relation between its angular displacement ( $θ$ ) and time (t) will be

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a

$θ α \sqrt{t}$

b

$θ α t^{3 / 2}$

c

$θ α t^{2}$

d

$θ α t$

answer is B.

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Detailed Solution

$α = \frac{ω}{t} = \frac{θ}{t^{2}} (∵ ω = \frac{θ}{t})$
when $α$ is constant, $θ α t^{2}$

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