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Q.

A body cools from 70^oC to 50^oC in 5 minutes. Temperature of surroundings is 20^o C. Its temperature after next 10 minutes is

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a

25^oC

b

35^oC

c

30^oC

d

45^oC

answer is C.

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Detailed Solution

$\frac{70 - 50}{5} = k (\frac{70 + 50}{5} - 20) k = \frac{1}{10}; \frac{50 - θ}{10} = \frac{1}{10} (\frac{50 + θ}{2} - 20); θ = 30^{o} C$

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