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Q.

A body dropped from the top of a tower covers a distance 9x in the last second of its journey, where x is the distance covered in first second.How much time does it take to reach the ground?

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a

4s

b

5s

c

3s

d

6s

answer is C.

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Detailed Solution

Last second $\to n^{t h}$ second
Question Image
$\begin{array}{l} S_{n} = 9 x \\ \frac{g}{2} (2 n - 1) = 9 x \end{array}$
x $\to$ Distance covered in 1st second (or) 1 second.
$\begin{array}{l} x = \frac{1}{2} g t^{2} = \frac{g}{2} \\ ∴ \frac{g}{2} (2 n - 1) = 9 (\frac{g}{2}) \\ 2 n - 2 = 9, n = 5 \end{array}$
$∴$ Time taken to reach the ground is 5 seconds.

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