A body executes simple harmonic motion the potential energy (PE),  the kinetic energy (KE) and total energy (TE) are measured as a function of displacement x. Which of the following statement is true?

At x=0, KE is maximum and PE is minimum

$\text{kinetic energy of simple harmonic oscillator is }$

$$\begin{gathered} = K=\frac{1}{2}{\text{mω}}^{\text{2}}{\text{(A}}^{\text{2}}{\text{-x}}^{\text{2}}\text{)} \\ \mathrm{When} \mathrm{x}=0, \mathrm{K}=\frac{1}{2}{\text{mω}}^{\text{2}}{\text{(A}}^{\text{2}}\text{) this is maximum energy } \end{gathered}$$

$\mathrm{potential}\text{ energy of simple }$

$\mathrm{harmonic} \mathrm{oscillator} \mathrm{is}$

$$\begin{gathered} = \mathrm{PE}==\frac{1}{2}{\text{mω}}^{\text{2}}{\text{(x}}^{\text{2}}\text{)} \\ \mathrm{When} \mathrm{x}=0, \mathrm{PE}=0 \end{gathered}$$

$\mathrm{total} \mathrm{energy} \mathrm{of} \mathrm{a} \mathrm{simple} \mathrm{harmonic} \mathrm{oscillator} =\mathrm{TE}=\frac{1}{2}{\text{mω}}^{\text{2}}{\text{(A}}^{\text{2}})=\mathrm{constant}$