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A body executing SHM has a maximum velocity 1m/sec and maximum acceleration of 4m/sec². Its amplitude in meters is

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0.75

0.25

0.5

answer is D.

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Detailed Solution

$ω = \frac{a_{max}}{v_{max}} = \frac{4}{1} = 4;$

$A = \frac{v_{max}}{ω} = \frac{1}{4} = 0 .25 m$

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