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Q.

A body falls freely under gravity from height h. Its gravitational potential energy and kinetic energy vs. time graph are shown in the figure. The correct variation is represented by :

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a

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b

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c

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d

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answer is B.

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Detailed Solution

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$\begin{array}{l} KE = \frac{1}{2} {mv}^{2} = \frac{1}{2} {mg}^{2} t^{2} \\ PE = mg (h - h_{1}) = mgh - \frac{1}{2} {mg}^{2} t^{2} \end{array}$

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A body falls freely under gravity from height h. Its gravitational potential energy and kinetic energy vs. time graph are shown in the figure. The correct variation is represented by :