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A body floats with one-third of its volume outside water and 3/4 th of its volume outside another liquid. The density of the liquid is :

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$\frac{9}{4} g / c c$

$\frac{8}{3} g / c c$

$\frac{4}{9} g / c c$

$\frac{3}{8} g / c c$

answer is C.

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Detailed Solution

$\frac{\frac{2}{3} = \frac{d_{b}}{d_{w}}}{\frac{1}{4} = \frac{d_{b}}{d_{l}}}$

$\begin{array}{l} \frac{8}{3} = \frac{d_{l}}{d_{w}} \\ \Rightarrow d_{l} = \frac{8}{3} g / c c \end{array}$

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