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A body is allowed to fall from a height h above the ground. Then match the following

List - I List - II
a) PE = KE e) at height h/2
b) PE = 2KE f) constant at any point
c) KE = 2PE g) at height 2h/3
d) PE + KE h) at height h/3

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a-f,b-g,c-e,d-h

a-e,b-h,c-g,d-f

a-g,b-e,c-f,d-h

a-e,b-g,c-h,d-f

answer is A.

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Detailed Solution

At a height y above the ground, $\frac{1}{2} m v^{2} + m g y = m g h v^{2} = 2 g (h - y)$

At any height, P.E.+K.E. = constant.
At y = h/2, KE = mg(h - h/2)=PE
At y = h/3, KE = mg(h - h/3)=2(PE)
At y = 2h/3, KE = mg(h - 2h/3)=1/2(PE)

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