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Q.

A body is allowed to fall from a height h above the ground. Then match the following
List - I                       List - II
a) PE = KE               e) at height h/2
b) PE = 2KE             f) constant at any point
c) KE = 2PE             g) at height 2h/3
d) PE + KE               h) at height h/3

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a

a-f,b-g,c-e,d-h

b

a-e,b-h,c-g,d-f

c

a-g,b-e,c-f,d-h

d

a-e,b-g,c-h,d-f

answer is A.

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Detailed Solution

Half of the total energy is transformed to kinetic energy when PE=KE. As a result, the original potential energy has been reduced to half. The ball must have dropped by h/2 as a result.

a - e

One-third of the total energy is transformed to kinetic energy when PE=2KE. The ball must have fallen by h/3 since the original potential energy has decreased to two-thirds of what it was.

b - g

Two thirds of the total energy are transformed to kinetic energy when 2PE=KE. As a result, just one-third of the initial potential energy remains. The ball must have dropped by 2h/3 as a result.

c - h

The entire energy of a system is preserved according to the law of energy conservation. TE+KE hence always equals constant.'

d - f

Hence the correct answer is a-e,b-g,c-h,d-f.

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