A body is displaced from (0, 0) to (1m, 1m) along the path x = y by a force F→=x2j^+yi^ N . The work done by this force will be

x=y ⇒dx=dyW=∫(0,0)(1,1)(x2.dy+y.dx)=∫(0,0)(1,1)(y2.dy+x.dx)=56

x=y ⇒dx=dyW=∫(0,0)(1,1)(x2.dy+y.dx)=∫(0,0)(1,1)(y2.dy+x.dx)=56

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A body is displaced from (0, 0) to (1m, 1m) along the path x = y by a force $\vec{F} = (x^{2} \hat{j} + y \hat{i}) N$ . The work done by this force will be

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answer is B.

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$x = y \Rightarrow dx = dy$

$W = \int_{(0, 0)}^{(1, 1)} (x^{2} . dy + y . dx) = \int_{(0, 0)}^{(1, 1)} (y^{2} . dy + x . dx) = \frac{5}{6}$

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