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Q.

A body is dropped from a height 122.5 m. If it is stopped after 3 seconds and again released, the further time of descent is (g=9.8 m/s2)

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a

2 s

b

4 s

c

3 s

d

5 s

answer is C.

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Detailed Solution

during 3s time height of fall 

h=12×9.8×32=44.1 Rem ht= 122.51-44.1=68.4m t= 2hg=2×68.49.8=4s

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