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Q.

A body is dropped from a height ‘h’. Speed of the body is ‘V’ when its loss in gravitational potential energy is U. The mass of the body is

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a

$\frac{U}{2 V^{2}}$

b

$\frac{V^{2}}{2 U}$

c

$\frac{U}{V^{2}}$

d

$\frac{2 U}{V^{2}}$

answer is C.

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Detailed Solution

Gain in K.E = loss in Gravitational Potential Energy

$\frac{1}{2} m v^{2} = U$

$m = \frac{2 U}{v^{2}}$

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A body is dropped from a height ‘h’. Speed of the body is ‘V’ when its loss in gravitational potential energy is U. The mass of the body is