A body is dropped from the top of the tower of  height ‘h’ after 1sec it is stopped and released what will be height after 2 sec  $\left(g=10m/s^2\right)$

The distance covered in 1sec  $S=10m;S=\frac{1}{2}g{t}^2$
The distance covered in next 2sec  $S=20m$
Total distances travelled down is $10+20=30m$
 The height of stone is  $\left(h-30\right)m$