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A body is executing simple harmonic motion with an angular frequency 2 rad/sec. The velocity of the body at 20 mm displacement. When the amplitude of motion is 60 mm is:

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40 mm/sec

113 mm/sec

120 mm/sec

60 mm/sec

answer is C.

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Detailed Solution

$v = ω \sqrt{a^{2} - y^{2}} = 2 \sqrt{{(60)}^{2} - {(20)}^{2}} = 113 m m / s e c$

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