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A body is moving in a vertical circle of radius r such that the string is just taut at its highest point. The speed of the particle when the string is horizontal is

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$\sqrt{3 g r}$

$\sqrt{4 g R}$

$\sqrt{2 g R}$

$\sqrt{g r}$

answer is C.

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Detailed Solution

v= $\sqrt{u^{2} - 2 g h}$ = $\sqrt{5 g r - 2 g r}$ = $\sqrt{3 g r}$

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