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A body is projected from a point on ground. It just clears two identical towers AB and CD at times 3S and 5 sec respectively if $g = 10 m / s^{2}$ , maximum height attained by the body is

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60 m

120 m

40 m

80 m

answer is D.

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Detailed Solution

Time of flight $T = (3 + 5) S = 8 S$

$∴ \frac{2 U \sin α}{g} = T \Rightarrow u \sin α = \frac{10 \times 8}{2} \frac{m}{s} = 40 \frac{m}{s}$

$∴ H_{\max} = \frac{{(u \sin α)}^{2}}{2 g} = \frac{{(40)}^{2}}{2 \times 10} m = 80 m$

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