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Q.

A body is projected from ground with a velocity u=40i^+30j^m/s.   Then  its  range  is  Takeg=10m/s2

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a

280 m

b

120 m

c

200 m

d

240 m

answer is A.

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Detailed Solution

(1)

   T=2usinθg=2×3010  sec=6sec.

   Range  R=4cosθ×T=40×6m=240m.

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