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A body is projected from ground with velocity 10 m/s at an angle $45^{o}$ from horizontal, if it clears a vertical wall after traveling horizontal distance 3 m. Then height of wall is, $(g = 10 m / s^{2})$

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0.9 m

3 m

5 m

2.1 m

answer is B.

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Detailed Solution

$y = 3 \times 1 [1 - \frac{3 \times 10}{100}]$

$y = 3 \times \frac{7}{10} = 2.1$

$x = \frac{10}{\sqrt{2}} \times \sqrt{\frac{21 \times 2}{10 \times 10}}$

$x = \frac{10}{\sqrt{2}} \times \frac{6.5}{10}$

$x = \approx 4 m$

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