A body is projected from the ground with a velocity u→=(3i^+10j^)ms−1 . The maximum height attained and the range of the body respectively are (given g = 10 ms-2)

U = 3i + 10JUx=3, Uy=10H=Uy22g=1002×10=5mUx×T=Ux×2Uyg=6m

A body is projected from the ground with a velocity u→=(3i^+10j^)ms−1 . The maximum height attained and the range of the body respectively are (given g = 10 ms-2)

U = 3i + 10JUx=3, Uy=10H=Uy22g=1002×10=5mUx×T=Ux×2Uyg=6m

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A body is projected from the ground with a velocity $\vec{u} = (3 \hat{i} + 10 \hat{j}) {ms}^{- 1}$ . The maximum height attained and the range of the body respectively are (given g = 10 ms^-2)

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6 m and 5 m

3 m and 5 m

5 m and 6 m

3 m and 10 m

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Detailed Solution

U = 3i + 10J
$U_{x} = 3, U_{y} = 10$
$H = \frac{U_{y}^{2}}{2 g} = \frac{100}{2 \times 10} = 5 m$
$U_{x} \times T = U_{x} \times \frac{2 U_{y}}{g} = 6 m$

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