Q.

A body is projected horizontally from a height of 5 m. It reaches the ground at a horizontal distance of 10 m. The speed of the particle when it reaches the ground is g=10 m/s2

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a

20 m/s

b

102 m/s

c

202 m/s

d

10 m/s

answer is B.

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Detailed Solution

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Time taken to reach the ground is t=2hg=2×510=1 s

Speed of projection is u=Rt=101=10 m/s

The horizontal component of velocity on reaching the ground is 

νx=u=10 m/s

The vertical component of velocity on reaching the ground is 

νy=2gh

=2×10×5=10 m/s

Speed on reaching the ground =νx2+νy2=102+102=102 m/s

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