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A body is projected horizontally from the top of a hill with a velocity of $9.8 m/s$ . What time elapses before the vertical velocity is twice the horizontal velocity

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Detailed Solution

u = 9.8 m/s

$v_{y} = 2 v_{x}$

$gt = 2 u$

$9 .8t = 2 (9.8)$

$t = 2 s$

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