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A body is projected horizontally from the top of a tower with a velocity of 20m/s. After what time the vertical component of velocity is four times the horizontal component of velocity? (g = 10m/s²)

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16 sec

8 sec

4 sec

2 sec

answer is B.

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Detailed Solution

$\vec{v} = u \hat{i} - gt \hat{j}$
As given V_y=4V_x
gt=4u
$∴ t = \frac{4 u}{g} = \frac{4 \times 200}{10} = 8 \sec$

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