A body is projected making an angle of 600 with horizontal from the base of an inclined plane having an inclination of 300 with horizontal. When the same body is projected vertically upward with same speed, maximum height attained by it is 45 m. Then its range on the inclined plane is

u2 sin26002×10 = 45 ⇒u2 =1200 m2/s2Therefore range on inclined plane = 2u2 sin (α-β)g cos2β = 2×1200×sin 30010×cos2300 m=80 m

A body is projected making an angle of 600 with horizontal from the base of an inclined plane having an inclination of 300 with horizontal. When the same body is projected vertically upward with same speed, maximum height attained by it is 45 m. Then its range on the inclined plane is

u2 sin26002×10 = 45 ⇒u2 =1200 m2/s2Therefore range on inclined plane = 2u2 sin (α-β)g cos2β = 2×1200×sin 30010×cos2300 m=80 m

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A body is projected making an angle of 60⁰ with horizontal from the base of an inclined plane having an inclination of 30⁰ with horizontal. When the same body is projected vertically upward with same speed, maximum height attained by it is 45 m. Then its range on the inclined plane is

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Detailed Solution

$\frac{u^{2} \sin^{2} 60^{0}}{2 \times 10} = 45 \Rightarrow u^{2} = 1200 m^{2} / s^{2}$

$T h e r e f o r e r a n g e o n i n c l i n e d p l a n e$

$= \frac{2 u^{2} \sin (α - β)}{g \cos^{2} β} = \frac{2 \times 1200 \times \sin 30^{0}}{10 \times \cos^{2} 30^{0}} m = 80 m$

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A body is projected making an angle of 600 with horizontal from the base of an inclined plane having an inclination of 300 with horizontal. When the same body is projected vertically upward with same speed, maximum height attained by it is 45 m. Then its range on the inclined plane is

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A body is projected making an angle of 60⁰ with horizontal from the base of an inclined plane having an inclination of 30⁰ with horizontal. When the same body is projected vertically upward with same speed, maximum height attained by it is 45 m. Then its range on the inclined plane is